4i-2(i-5)=-9+4i+11

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Solution for 4i-2(i-5)=-9+4i+11 equation: 



4i-2(i-5)=-9+4i+11

We move all terms to the left:

4i-2(i-5)-(-9+4i+11)=0

We add all the numbers together, and all the variables

4i-2(i-5)-(4i+2)=0

We multiply parentheses

4i-2i-(4i+2)+10=0

We get rid of parentheses

4i-2i-4i-2+10=0

We add all the numbers together, and all the variables

-2i+8=0

We move all terms containing i to the left, all other terms to the right

-2i=-8

i=-8/-2

i=+4

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