4g+3(g-2)=5(g-4)-g

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Solution for 4g+3(g-2)=5(g-4)-g equation: 



4g+3(g-2)=5(g-4)-g

We move all terms to the left:

4g+3(g-2)-(5(g-4)-g)=0

We multiply parentheses

4g+3g-(5(g-4)-g)-6=0



We calculate terms in parentheses: -(5(g-4)-g), so:

5(g-4)-g

We add all the numbers together, and all the variables

-1g+5(g-4)

We multiply parentheses

-1g+5g-20

We add all the numbers together, and all the variables

4g-20

Back to the equation:

-(4g-20)



We add all the numbers together, and all the variables

7g-(4g-20)-6=0

We get rid of parentheses

7g-4g+20-6=0

We add all the numbers together, and all the variables

3g+14=0

We move all terms containing g to the left, all other terms to the right

3g=-14

g=-14/3

g=-4+2/3

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