4cos^4x-(7cos^2x)+3=0

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Solution for 4cos^4x-(7cos^2x)+3=0 equation:


Simplifying
4cos4x + -1(7cos2x) + 3 = 0

Remove parenthesis around (7cos2x)
4cos4x + -1 * 7cos2x + 3 = 0

Multiply -1 * 7
4cos4x + -7cos2x + 3 = 0

Reorder the terms:
3 + -7cos2x + 4cos4x = 0

Solving
3 + -7cos2x + 4cos4x = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -7cos2x + -3 + 4cos4x = 0 + -3

Reorder the terms:
3 + -3 + -7cos2x + 4cos4x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -7cos2x + 4cos4x = 0 + -3
-7cos2x + 4cos4x = 0 + -3

Combine like terms: 0 + -3 = -3
-7cos2x + 4cos4x = -3

Reorder the terms:
3 + -7cos2x + 4cos4x = -3 + 3

Combine like terms: -3 + 3 = 0
3 + -7cos2x + 4cos4x = 0

The solution to this equation could not be determined.

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