4c=3c+(-8)

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Solution for 4c=3c+(-8) equation: 



4c=3c+(-8)

We move all terms to the left:

4c-(3c+(-8))=0



We calculate terms in parentheses: -(3c+(-8)), so:

3c+(-8)

We add all the numbers together, and all the variables

3c-8

Back to the equation:

-(3c-8)



We get rid of parentheses

4c-3c+8=0

We add all the numbers together, and all the variables

c+8=0

We move all terms containing c to the left, all other terms to the right

c=-8

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