4c+3=3(c+-4)

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Solution for 4c+3=3(c+-4) equation: 



4c+3=3(c+-4)

We move all terms to the left:

4c+3-(3(c+-4))=0

We add all the numbers together, and all the variables

4c-(3(c-4))+3=0



We calculate terms in parentheses: -(3(c-4)), so:

3(c-4)

We multiply parentheses

3c-12

Back to the equation:

-(3c-12)



We get rid of parentheses

4c-3c+12+3=0

We add all the numbers together, and all the variables

c+15=0

We move all terms containing c to the left, all other terms to the right

c=-15

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