4c+3(2+c)=4c+6+3c

Solution for 4c+3(2+c)=4c+6+3c equation:

Simplifying
4c + 3(2 + c) = 4c + 6 + 3c
4c + (2 * 3 + c * 3) = 4c + 6 + 3c
4c + (6 + 3c) = 4c + 6 + 3c

Reorder the terms:
6 + 4c + 3c = 4c + 6 + 3c

Combine like terms: 4c + 3c = 7c
6 + 7c = 4c + 6 + 3c

Reorder the terms:
6 + 7c = 6 + 4c + 3c

Combine like terms: 4c + 3c = 7c
6 + 7c = 6 + 7c

Add '-6' to each side of the equation.
6 + -6 + 7c = 6 + -6 + 7c

Combine like terms: 6 + -6 = 0
0 + 7c = 6 + -6 + 7c
7c = 6 + -6 + 7c

Combine like terms: 6 + -6 = 0
7c = 0 + 7c
7c = 7c

Add '-7c' to each side of the equation.
7c + -7c = 7c + -7c

Combine like terms: 7c + -7c = 0
0 = 7c + -7c

Combine like terms: 7c + -7c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.