4c(8c-4)=16

Solution for 4c(8c-4)=16 equation:

4c(8c-4)=16

We move all terms to the left:

4c(8c-4)-(16)=0

We multiply parentheses

32c^2-16c-16=0

a = 32; b = -16; c = -16;
Δ = b2-4ac
Δ = -162-4·32·(-16)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-48}{2*32}=\frac{-32}{64}
=-1/2
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+48}{2*32}=\frac{64}{64}
=1
$