4b+35=7(b-2)+4b

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Solution for 4b+35=7(b-2)+4b equation: 



4b+35=7(b-2)+4b

We move all terms to the left:

4b+35-(7(b-2)+4b)=0



We calculate terms in parentheses: -(7(b-2)+4b), so:

7(b-2)+4b

We add all the numbers together, and all the variables

4b+7(b-2)

We multiply parentheses

4b+7b-14

We add all the numbers together, and all the variables

11b-14

Back to the equation:

-(11b-14)



We get rid of parentheses

4b-11b+14+35=0

We add all the numbers together, and all the variables

-7b+49=0

We move all terms containing b to the left, all other terms to the right

-7b=-49

b=-49/-7

b=+7

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