4b+3/4b-1=b+1/b-1

Solution for 4b+3/4b-1=b+1/b-1 equation:

4b+3/4b-1=b+1/b-1

We move all terms to the left:

4b+3/4b-1-(b+1/b-1)=0


Domain of the equation: 4b!=0

b!=0/4

b!=0

b∈R



Domain of the equation: b-1)!=0

b∈R


We get rid of parentheses

4b+3/4b-b-1/b+1-1=0

We calculate fractions


4b-b+3b/4b^2+(-4b)/4b^2+1-1=0

We add all the numbers together, and all the variables

3b+3b/4b^2+(-4b)/4b^2=0

We multiply all the terms by the denominator


3b*4b^2+3b+(-4b)=0

We add all the numbers together, and all the variables

3b+3b*4b^2+(-4b)=0

Wy multiply elements

12b^3+3b+(-4b)=0

We get rid of parentheses

12b^3+3b-4b=0

We do not support ebpression: b^3