4b+2b=32

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Solution for 4b+2b=32 equation: 



4b+2b=32

We move all terms to the left:

4b+2b-(32)=0

We add all the numbers together, and all the variables

6b-32=0

We move all terms containing b to the left, all other terms to the right

6b=32

b=32/6

b=5+1/3

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