4b(b+6)=0

Solution for 4b(b+6)=0 equation:

4b(b+6)=0

We multiply parentheses

4b^2+24b=0

a = 4; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·4·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*4}=\frac{-48}{8}
=-6
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*4}=\frac{0}{8}
=0
$