4a-4=3+12(a+3)

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Solution for 4a-4=3+12(a+3) equation: 



4a-4=3+12(a+3)

We move all terms to the left:

4a-4-(3+12(a+3))=0



We calculate terms in parentheses: -(3+12(a+3)), so:

3+12(a+3)

determiningTheFunctionDomain
12(a+3)+3

We multiply parentheses

12a+36+3

We add all the numbers together, and all the variables

12a+39

Back to the equation:

-(12a+39)



We get rid of parentheses

4a-12a-39-4=0

We add all the numbers together, and all the variables

-8a-43=0

We move all terms containing a to the left, all other terms to the right

-8a=43

a=43/-8

a=-5+3/8

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