4a-3(1+4a)=-(6a-3)

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Solution for 4a-3(1+4a)=-(6a-3) equation: 



4a-3(1+4a)=-(6a-3)

We move all terms to the left:

4a-3(1+4a)-(-(6a-3))=0

We add all the numbers together, and all the variables

4a-3(4a+1)-(-(6a-3))=0

We multiply parentheses

4a-12a-(-(6a-3))-3=0



We calculate terms in parentheses: -(-(6a-3)), so:

-(6a-3)

We get rid of parentheses

-6a+3

Back to the equation:

-(-6a+3)



We add all the numbers together, and all the variables

-8a-(-6a+3)-3=0

We get rid of parentheses

-8a+6a-3-3=0

We add all the numbers together, and all the variables

-2a-6=0

We move all terms containing a to the left, all other terms to the right

-2a=6

a=6/-2

a=-3

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