4a-(6-3a)=10

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Solution for 4a-(6-3a)=10 equation: 



4a-(6-3a)=10

We move all terms to the left:

4a-(6-3a)-(10)=0

We add all the numbers together, and all the variables

4a-(-3a+6)-10=0

We get rid of parentheses

4a+3a-6-10=0

We add all the numbers together, and all the variables

7a-16=0

We move all terms containing a to the left, all other terms to the right

7a=16

a=16/7

a=2+2/7

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