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4a+5(1+3a)=5(1+4a)
We move all terms to the left:
4a+5(1+3a)-(5(1+4a))=0
We add all the numbers together, and all the variables
4a+5(3a+1)-(5(4a+1))=0
We multiply parentheses
4a+15a-(5(4a+1))+5=0
We calculate terms in parentheses: -(5(4a+1)), so:We add all the numbers together, and all the variables
5(4a+1)
We multiply parentheses
20a+5
Back to the equation:
-(20a+5)
19a-(20a+5)+5=0
We get rid of parentheses
19a-20a-5+5=0
We add all the numbers together, and all the variables
-a=0
a=0/-1
a=0
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