4a+3(6a-3)=101

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Solution for 4a+3(6a-3)=101 equation: 



4a+3(6a-3)=101

We move all terms to the left:

4a+3(6a-3)-(101)=0

We multiply parentheses

4a+18a-9-101=0

We add all the numbers together, and all the variables

22a-110=0

We move all terms containing a to the left, all other terms to the right

22a=110

a=110/22

a=5

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