4a+2b+c=c+2b+4a

Solution for 4a+2b+c=c+2b+4a equation:

Simplifying
4a + 2b + c = c + 2b + 4a

Reorder the terms:
4a + 2b + c = 4a + 2b + c

Add '-4a' to each side of the equation.
4a + 2b + -4a + c = 4a + 2b + -4a + c

Reorder the terms:
4a + -4a + 2b + c = 4a + 2b + -4a + c

Combine like terms: 4a + -4a = 0
0 + 2b + c = 4a + 2b + -4a + c
2b + c = 4a + 2b + -4a + c

Reorder the terms:
2b + c = 4a + -4a + 2b + c

Combine like terms: 4a + -4a = 0
2b + c = 0 + 2b + c
2b + c = 2b + c

Add '-2b' to each side of the equation.
2b + -2b + c = 2b + -2b + c

Combine like terms: 2b + -2b = 0
0 + c = 2b + -2b + c
c = 2b + -2b + c

Combine like terms: 2b + -2b = 0
c = 0 + c
c = c

Add '-1c' to each side of the equation.
c + -1c = c + -1c

Combine like terms: c + -1c = 0
0 = c + -1c

Combine like terms: c + -1c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.