4a+2(3a-4)=-4a+7(a+1)

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Solution for 4a+2(3a-4)=-4a+7(a+1) equation: 



4a+2(3a-4)=-4a+7(a+1)

We move all terms to the left:

4a+2(3a-4)-(-4a+7(a+1))=0

We multiply parentheses

4a+6a-(-4a+7(a+1))-8=0



We calculate terms in parentheses: -(-4a+7(a+1)), so:

-4a+7(a+1)

We multiply parentheses

-4a+7a+7

We add all the numbers together, and all the variables

3a+7

Back to the equation:

-(3a+7)



We add all the numbers together, and all the variables

10a-(3a+7)-8=0

We get rid of parentheses

10a-3a-7-8=0

We add all the numbers together, and all the variables

7a-15=0

We move all terms containing a to the left, all other terms to the right

7a=15

a=15/7

a=2+1/7

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