4a+10=6(a+1)-2(a-2)

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Solution for 4a+10=6(a+1)-2(a-2) equation: 



4a+10=6(a+1)-2(a-2)

We move all terms to the left:

4a+10-(6(a+1)-2(a-2))=0



We calculate terms in parentheses: -(6(a+1)-2(a-2)), so:

6(a+1)-2(a-2)

We multiply parentheses

6a-2a+6+4

We add all the numbers together, and all the variables

4a+10

Back to the equation:

-(4a+10)



We get rid of parentheses

4a-4a-10+10=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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