4a*a=329

Solution for 4a*a=329 equation:

4a*a=329

We move all terms to the left:

4a*a-(329)=0

Wy multiply elements

4a^2-329=0

a = 4; b = 0; c = -329;
Δ = b2-4ac
Δ = 02-4·4·(-329)
Δ = 5264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5264}=\sqrt{16*329}=\sqrt{16}*\sqrt{329}=4\sqrt{329}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{329}}{2*4}=\frac{0-4\sqrt{329}}{8}
=-\frac{4\sqrt{329}}{8}
=-\frac{\sqrt{329}}{2}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{329}}{2*4}=\frac{0+4\sqrt{329}}{8}
=\frac{4\sqrt{329}}{8}
=\frac{\sqrt{329}}{2}
$