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4X^2+5X-9000=0
a = 4; b = 5; c = -9000;
Δ = b2-4ac
Δ = 52-4·4·(-9000)
Δ = 144025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{144025}=\sqrt{25*5761}=\sqrt{25}*\sqrt{5761}=5\sqrt{5761}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5\sqrt{5761}}{2*4}=\frac{-5-5\sqrt{5761}}{8} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5\sqrt{5761}}{2*4}=\frac{-5+5\sqrt{5761}}{8} $
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