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4=11-6/5z
We move all terms to the left:
4-(11-6/5z)=0
Domain of the equation: 5z)!=0We add all the numbers together, and all the variables
z!=0/1
z!=0
z∈R
-(-6/5z+11)+4=0
We get rid of parentheses
6/5z-11+4=0
We multiply all the terms by the denominator
-11*5z+4*5z+6=0
Wy multiply elements
-55z+20z+6=0
We add all the numbers together, and all the variables
-35z+6=0
We move all terms containing z to the left, all other terms to the right
-35z=-6
z=-6/-35
z=6/35
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