4=1+2(n-1)

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Solution for 4=1+2(n-1) equation: 



4=1+2(n-1)

We move all terms to the left:

4-(1+2(n-1))=0



We calculate terms in parentheses: -(1+2(n-1)), so:

1+2(n-1)

determiningTheFunctionDomain
2(n-1)+1

We multiply parentheses

2n-2+1

We add all the numbers together, and all the variables

2n-1

Back to the equation:

-(2n-1)



We get rid of parentheses

-2n+1+4=0

We add all the numbers together, and all the variables

-2n+5=0

We move all terms containing n to the left, all other terms to the right

-2n=-5

n=-5/-2

n=2+1/2

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