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4=-x2+3x-8
We move all terms to the left:
4-(-x2+3x-8)=0
We add all the numbers together, and all the variables
-(-1x^2+3x-8)+4=0
We get rid of parentheses
1x^2-3x+8+4=0
We add all the numbers together, and all the variables
x^2-3x+12=0
a = 1; b = -3; c = +12;
Δ = b2-4ac
Δ = -32-4·1·12
Δ = -39
Delta is less than zero, so there is no solution for the equation
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