4=-3(2z+2)+7z

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Solution for 4=-3(2z+2)+7z equation: 



4=-3(2z+2)+7z

We move all terms to the left:

4-(-3(2z+2)+7z)=0



We calculate terms in parentheses: -(-3(2z+2)+7z), so:

-3(2z+2)+7z

We add all the numbers together, and all the variables

7z-3(2z+2)

We multiply parentheses

7z-6z-6

We add all the numbers together, and all the variables

z-6

Back to the equation:

-(z-6)



We get rid of parentheses

-z+6+4=0

We add all the numbers together, and all the variables

-1z+10=0

We move all terms containing z to the left, all other terms to the right

-z=-10

z=-10/-1

z=+10

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