4=(7c+3)+5

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Solution for 4=(7c+3)+5 equation: 



4=(7c+3)+5

We move all terms to the left:

4-((7c+3)+5)=0



We calculate terms in parentheses: -((7c+3)+5), so:

(7c+3)+5

We get rid of parentheses

7c+3+5

We add all the numbers together, and all the variables

7c+8

Back to the equation:

-(7c+8)



We get rid of parentheses

-7c-8+4=0

We add all the numbers together, and all the variables

-7c-4=0

We move all terms containing c to the left, all other terms to the right

-7c=4

c=4/-7

c=-4/7

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