4=(2+2c)

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Solution for 4=(2+2c) equation: 



4=(2+2c)

We move all terms to the left:

4-((2+2c))=0

We add all the numbers together, and all the variables

-((2c+2))+4=0



We calculate terms in parentheses: -((2c+2)), so:

(2c+2)

We get rid of parentheses

2c+2

Back to the equation:

-(2c+2)



We get rid of parentheses

-2c-2+4=0

We add all the numbers together, and all the variables

-2c+2=0

We move all terms containing c to the left, all other terms to the right

-2c=-2

c=-2/-2

c=1

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