4=(1/8)(3x+16)

Solution for 4=(1/8)(3x+16) equation:

4=(1/8)(3x+16)

We move all terms to the left:

4-((1/8)(3x+16))=0


Domain of the equation: 8)(3x+16))!=0

x∈R


We add all the numbers together, and all the variables

-((+1/8)(3x+16))+4=0

We multiply parentheses ..

-((+3x^2+1/8*16))+4=0

We multiply all the terms by the denominator


-((+3x^2+1+4*8*16))=0


We calculate terms in parentheses: -((+3x^2+1+4*8*16)), so:

(+3x^2+1+4*8*16)

We get rid of parentheses

3x^2+1+4*8*16

We add all the numbers together, and all the variables

3x^2+513

Back to the equation:

-(3x^2+513)


We get rid of parentheses

-3x^2-513=0

a = -3; b = 0; c = -513;
Δ = b2-4ac
Δ = 02-4·(-3)·(-513)
Δ = -6156
Delta is less than zero, so there is no solution for the equation