4=(1/3)(7x-3)

Solution for 4=(1/3)(7x-3) equation:

4=(1/3)(7x-3)

We move all terms to the left:

4-((1/3)(7x-3))=0


Domain of the equation: 3)(7x-3))!=0

x∈R


We add all the numbers together, and all the variables

-((+1/3)(7x-3))+4=0

We multiply parentheses ..

-((+7x^2+1/3*-3))+4=0

We multiply all the terms by the denominator


-((+7x^2+1+4*3*-3))=0


We calculate terms in parentheses: -((+7x^2+1+4*3*-3)), so:

(+7x^2+1+4*3*-3)

We get rid of parentheses

7x^2+1-3+4*3*

We add all the numbers together, and all the variables

7x^2

Back to the equation:

-(7x^2)


a = -7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-7)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-14}=0$