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4=(-2/3)(5)+x
We move all terms to the left:
4-((-2/3)(5)+x)=0
Domain of the equation: 3)5+x)!=0We multiply all the terms by the denominator
x!=0/1
x!=0
x∈R
-((-2+4*3)5+x)=0
We calculate terms in parentheses: -((-2+4*3)5+x), so:We get rid of parentheses
(-2+4*3)5+x
determiningTheFunctionDomain x+(-2+4*3)5
We add all the numbers together, and all the variables
x+105
Back to the equation:
-(x+105)
-x-105=0
We add all the numbers together, and all the variables
-1x-105=0
We move all terms containing x to the left, all other terms to the right
-x=105
x=105/-1
x=-105
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