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49x^2=121
We move all terms to the left:
49x^2-(121)=0
a = 49; b = 0; c = -121;
Δ = b2-4ac
Δ = 02-4·49·(-121)
Δ = 23716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{23716}=154$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-154}{2*49}=\frac{-154}{98} =-1+4/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+154}{2*49}=\frac{154}{98} =1+4/7 $
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