49x2-21x-10=0

Solution for 49x2-21x-10=0 equation:

49x^2-21x-10=0

a = 49; b = -21; c = -10;
Δ = b2-4ac
Δ = -212-4·49·(-10)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-49}{2*49}=\frac{-28}{98}
=-2/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+49}{2*49}=\frac{70}{98}
=5/7
$