49(2x+1)=7(3x+7)

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Solution for 49(2x+1)=7(3x+7) equation: 



49(2x+1)=7(3x+7)

We move all terms to the left:

49(2x+1)-(7(3x+7))=0

We multiply parentheses

98x-(7(3x+7))+49=0



We calculate terms in parentheses: -(7(3x+7)), so:

7(3x+7)

We multiply parentheses

21x+49

Back to the equation:

-(21x+49)



We get rid of parentheses

98x-21x-49+49=0

We add all the numbers together, and all the variables

77x=0

x=0/77

x=0

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