48x2-4-6=0

Solution for 48x2-4-6=0 equation:

48x^2-4-6=0

We add all the numbers together, and all the variables

48x^2-10=0

a = 48; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·48·(-10)
Δ = 1920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1920}=\sqrt{64*30}=\sqrt{64}*\sqrt{30}=8\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{30}}{2*48}=\frac{0-8\sqrt{30}}{96}
=-\frac{8\sqrt{30}}{96}
=-\frac{\sqrt{30}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{30}}{2*48}=\frac{0+8\sqrt{30}}{96}
=\frac{8\sqrt{30}}{96}
=\frac{\sqrt{30}}{12}
$