48x2+58x-8=0

Solution for 48x2+58x-8=0 equation:

48x^2+58x-8=0

a = 48; b = 58; c = -8;
Δ = b2-4ac
Δ = 582-4·48·(-8)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-70}{2*48}=\frac{-128}{96}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+70}{2*48}=\frac{12}{96}
=1/8
$