48x2+240x-1800=0

Solution for 48x2+240x-1800=0 equation:

48x^2+240x-1800=0

a = 48; b = 240; c = -1800;
Δ = b2-4ac
Δ = 2402-4·48·(-1800)
Δ = 403200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{403200}=\sqrt{57600*7}=\sqrt{57600}*\sqrt{7}=240\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(240)-240\sqrt{7}}{2*48}=\frac{-240-240\sqrt{7}}{96}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(240)+240\sqrt{7}}{2*48}=\frac{-240+240\sqrt{7}}{96}
$