48=4(k+28)

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Solution for 48=4(k+28) equation: 



48=4(k+28)

We move all terms to the left:

48-(4(k+28))=0



We calculate terms in parentheses: -(4(k+28)), so:

4(k+28)

We multiply parentheses

4k+112

Back to the equation:

-(4k+112)



We get rid of parentheses

-4k-112+48=0

We add all the numbers together, and all the variables

-4k-64=0

We move all terms containing k to the left, all other terms to the right

-4k=64

k=64/-4

k=-16

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