48=(3x+3x)+(4x+4x)+(7x+6)

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Solution for 48=(3x+3x)+(4x+4x)+(7x+6) equation: 



48=(3x+3x)+(4x+4x)+(7x+6)

We move all terms to the left:

48-((3x+3x)+(4x+4x)+(7x+6))=0

We add all the numbers together, and all the variables

-((+6x)+(+8x)+(7x+6))+48=0



We calculate terms in parentheses: -((+6x)+(+8x)+(7x+6)), so:

(+6x)+(+8x)+(7x+6)

We get rid of parentheses

6x+8x+7x+6

We add all the numbers together, and all the variables

21x+6

Back to the equation:

-(21x+6)



We get rid of parentheses

-21x-6+48=0

We add all the numbers together, and all the variables

-21x+42=0

We move all terms containing x to the left, all other terms to the right

-21x=-42

x=-42/-21

x=+2

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