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480t=660(t-1/2)
We move all terms to the left:
480t-(660(t-1/2))=0
We add all the numbers together, and all the variables
480t-(660(+t-1/2))=0
We multiply all the terms by the denominator
480t*2))-(660(+t-1=0
We add all the numbers together, and all the variables
t+480t*2))-(660(-1=0
Wy multiply elements
960t^2+t-1=0
a = 960; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·960·(-1)
Δ = 3841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{3841}}{2*960}=\frac{-1-\sqrt{3841}}{1920} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{3841}}{2*960}=\frac{-1+\sqrt{3841}}{1920} $
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