480=x^2

Solution for 480=x^2 equation:

480=x^2

We move all terms to the left:

480-(x^2)=0

We add all the numbers together, and all the variables

-1x^2+480=0

a = -1; b = 0; c = +480;
Δ = b2-4ac
Δ = 02-4·(-1)·480
Δ = 1920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1920}=\sqrt{64*30}=\sqrt{64}*\sqrt{30}=8\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{30}}{2*-1}=\frac{0-8\sqrt{30}}{-2}
=-\frac{8\sqrt{30}}{-2}
=-\frac{4\sqrt{30}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{30}}{2*-1}=\frac{0+8\sqrt{30}}{-2}
=\frac{8\sqrt{30}}{-2}
=\frac{4\sqrt{30}}{-1}
$