48-3x(x-4)=3x

Solution for 48-3x(x-4)=3x equation:

48-3x(x-4)=3x

We move all terms to the left:

48-3x(x-4)-(3x)=0

We add all the numbers together, and all the variables

-3x-3x(x-4)+48=0

We multiply parentheses

-3x^2-3x+12x+48=0

We add all the numbers together, and all the variables

-3x^2+9x+48=0

a = -3; b = 9; c = +48;
Δ = b2-4ac
Δ = 92-4·(-3)·48
Δ = 657
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{657}=\sqrt{9*73}=\sqrt{9}*\sqrt{73}=3\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3\sqrt{73}}{2*-3}=\frac{-9-3\sqrt{73}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3\sqrt{73}}{2*-3}=\frac{-9+3\sqrt{73}}{-6}
$