48-(3c+4)=4(c+7)+6

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Solution for 48-(3c+4)=4(c+7)+6 equation: 



48-(3c+4)=4(c+7)+6

We move all terms to the left:

48-(3c+4)-(4(c+7)+6)=0

We get rid of parentheses

-3c-(4(c+7)+6)-4+48=0



We calculate terms in parentheses: -(4(c+7)+6), so:

4(c+7)+6

We multiply parentheses

4c+28+6

We add all the numbers together, and all the variables

4c+34

Back to the equation:

-(4c+34)



We add all the numbers together, and all the variables

-3c-(4c+34)+44=0

We get rid of parentheses

-3c-4c-34+44=0

We add all the numbers together, and all the variables

-7c+10=0

We move all terms containing c to the left, all other terms to the right

-7c=-10

c=-10/-7

c=1+3/7

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