48-(3c+4)=2(c-7)+c

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Solution for 48-(3c+4)=2(c-7)+c equation: 



48-(3c+4)=2(c-7)+c

We move all terms to the left:

48-(3c+4)-(2(c-7)+c)=0

We get rid of parentheses

-3c-(2(c-7)+c)-4+48=0



We calculate terms in parentheses: -(2(c-7)+c), so:

2(c-7)+c

We add all the numbers together, and all the variables

c+2(c-7)

We multiply parentheses

c+2c-14

We add all the numbers together, and all the variables

3c-14

Back to the equation:

-(3c-14)



We add all the numbers together, and all the variables

-3c-(3c-14)+44=0

We get rid of parentheses

-3c-3c+14+44=0

We add all the numbers together, and all the variables

-6c+58=0

We move all terms containing c to the left, all other terms to the right

-6c=-58

c=-58/-6

c=9+2/3

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