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48+90-x=2/3x-180
We move all terms to the left:
48+90-x-(2/3x-180)=0
Domain of the equation: 3x-180)!=0We add all the numbers together, and all the variables
x∈R
-1x-(2/3x-180)+138=0
We get rid of parentheses
-1x-2/3x+180+138=0
We multiply all the terms by the denominator
-1x*3x+180*3x+138*3x-2=0
Wy multiply elements
-3x^2+540x+414x-2=0
We add all the numbers together, and all the variables
-3x^2+954x-2=0
a = -3; b = 954; c = -2;
Δ = b2-4ac
Δ = 9542-4·(-3)·(-2)
Δ = 910092
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{910092}=\sqrt{4*227523}=\sqrt{4}*\sqrt{227523}=2\sqrt{227523}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(954)-2\sqrt{227523}}{2*-3}=\frac{-954-2\sqrt{227523}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(954)+2\sqrt{227523}}{2*-3}=\frac{-954+2\sqrt{227523}}{-6} $
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