48+.99(n-1)=0+1.29(n-1)

Solution for 48+.99(n-1)=0+1.29(n-1) equation:

48+.99(n-1)=0+1.29(n-1)

We move all terms to the left:

48+.99(n-1)-(0+1.29(n-1))=0

We multiply parentheses

0.99n-(0+1.29(n-1))-0.99+48=0


We calculate terms in parentheses: -(0+1.29(n-1)), so:

0+1.29(n-1)

determiningTheFunctionDomain
1.29(n-1)+0

We add all the numbers together, and all the variables

1.29(n-1)

We multiply parentheses

1.29n-1.29

Back to the equation:

-(1.29n-1.29)


We add all the numbers together, and all the variables

0.99n-(1.29n-1.29)+47.01=0

We get rid of parentheses

0.99n-1.29n+1.29+47.01=0

We add all the numbers together, and all the variables

-0.3n+48.3=0

We move all terms containing n to the left, all other terms to the right

-0.3n=-48.3

n=-48.3/-0.3

n=+161