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48(x+15)2x=60
We move all terms to the left:
48(x+15)2x-(60)=0
We multiply parentheses
96x^2+1440x-60=0
a = 96; b = 1440; c = -60;
Δ = b2-4ac
Δ = 14402-4·96·(-60)
Δ = 2096640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2096640}=\sqrt{2304*910}=\sqrt{2304}*\sqrt{910}=48\sqrt{910}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1440)-48\sqrt{910}}{2*96}=\frac{-1440-48\sqrt{910}}{192} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1440)+48\sqrt{910}}{2*96}=\frac{-1440+48\sqrt{910}}{192} $
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