47=4(n-5)+5(-3-2)

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Solution for 47=4(n-5)+5(-3-2) equation: 



47=4(n-5)+5(-3-2)

We move all terms to the left:

47-(4(n-5)+5(-3-2))=0

We add all the numbers together, and all the variables

-(4(n-5)+5(-5))+47=0



We calculate terms in parentheses: -(4(n-5)+5(-5)), so:

4(n-5)+5(-5)

We add all the numbers together, and all the variables

4(n-5)-25

We multiply parentheses

4n-20-25

We add all the numbers together, and all the variables

4n-45

Back to the equation:

-(4n-45)



We get rid of parentheses

-4n+45+47=0

We add all the numbers together, and all the variables

-4n+92=0

We move all terms containing n to the left, all other terms to the right

-4n=-92

n=-92/-4

n=+23

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