47=4(n-5)+(-3n-2)

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Solution for 47=4(n-5)+(-3n-2) equation: 



47=4(n-5)+(-3n-2)

We move all terms to the left:

47-(4(n-5)+(-3n-2))=0



We calculate terms in parentheses: -(4(n-5)+(-3n-2)), so:

4(n-5)+(-3n-2)

We multiply parentheses

4n+(-3n-2)-20

We get rid of parentheses

4n-3n-2-20

We add all the numbers together, and all the variables

n-22

Back to the equation:

-(n-22)



We get rid of parentheses

-n+22+47=0

We add all the numbers together, and all the variables

-1n+69=0

We move all terms containing n to the left, all other terms to the right

-n=-69

n=-69/-1

n=+69

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