47=(x+5)(x-5)

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Solution for 47=(x+5)(x-5) equation: 



47=(x+5)(x-5)

We move all terms to the left:

47-((x+5)(x-5))=0

We use the square of the difference formula

x^2+25+47=0

We add all the numbers together, and all the variables

x^2+72=0

a = 1; b = 0; c = +72;
Δ = b2-4ac
Δ = 02-4·1·72
Δ = -288
Delta is less than zero, so there is no solution for the equation

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