47-4z=5(z-5)

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Solution for 47-4z=5(z-5) equation: 



47-4z=5(z-5)

We move all terms to the left:

47-4z-(5(z-5))=0



We calculate terms in parentheses: -(5(z-5)), so:

5(z-5)

We multiply parentheses

5z-25

Back to the equation:

-(5z-25)



We get rid of parentheses

-4z-5z+25+47=0

We add all the numbers together, and all the variables

-9z+72=0

We move all terms containing z to the left, all other terms to the right

-9z=-72

z=-72/-9

z=+8

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